The electrostatic transducer is also capable of detecting ultrasonic sound. When an ultrasonic sound wave enters the electrostatic transducer, the wave (which is simply a perturbation in pressure) hits the gold foil. The extra air pressure associated with this wave causes the gold foil to move toward the aluminum plate compressing the Kapton dielectric in the process. It is a well known fact from electromagnetism that q = C x V, where q is equal to the charge, C is the capacitance, and V is the voltage difference between the two plates. The charge on the plates remains the same when the transducer is in its sound detection mode, so q remains constant. However, the capacitance, C, will increase when the distance between the plates decreases. Thus, when the sound wave hit the gold foil, the capacitance increases because the distance between the plates decreases. The voltage has to decrease because the charge on the plates remains the same. This change in voltage creates an electrical signal allowing one to know when the electrostatic transducer detects sound.